Hi everyone, I'm posting this for two reasons. One, I need some feedback on the method and Two, I just wanted to share it so we can all benefit from it.
The method works like so.
1) Requires at least 2 viewers, the more the merrier.
2) Each viewer is required to complete 2x(number of lottery values -1 ) so in the case of 649 (Canada) you need to complete 10 targets for a winning ticket.
3) There is some possible front loading
4) The 3 images must be as unique as possible from one another, they should not share anything in common.
The theory is based on a type of compression.
For example
All numbers have a mathematical gap and any combination of numbers have a gap of Total numbers -1.
Take this for example.
1,4,9,10
These 4 numbers can also be defined as
3,5,1
Meaning the difference between these numbers are 3, 5 and 1. Of course, this created more than one possible combination per result but it does create a very large advantage per set of numbers.
I've taken the common 6x49 combination and layed it out in chart form, see below.
In the charted example you should notice that it requires 2 things to be viewed. 1 of 16 types of shapes and 1 of three targets. The simplier the shapes the easier the analysis but keep each shape/color as unique as possible. Don't use a red square and an orange rectangle!
The shapes can obviously be substituted with other items, but for simplicity I've created this example with these.
The 3 images should also be unique, for example
Image 1 = Space Shuttle
Image 3 = Shopping mall
Image 3 = Tree
So if the 1st number on the lottery ticket is 1 we should get corroborating sessions as such.
Session 1a) Red Circle
Session 1b) Space Shuttle
If the second number was 12 we should have
session 2a) Blue Triangle
Session 2b) Shopping Mall
Once we get all of the 4 values, we can then create our span values.
In the case of the first example 3,5,1 we would start with
1,4,9,10
2,5,10,11
3,6,11,12
The number of combinations would be equal to (Largest Lotto Value - Largest "SPAN" Value).
So if our lotto had 49 values and out last "SPAN" value was 22, then the total number of combinations would be 27.
This process can be applied to any lottery, you'll just need to modify the chart to correspond to the numbers.
Having said all of this, we still need to CUE the results.
This is where I would need some feedback.
You would need these "symbols" either in real form such as childrens blocks/toys or physical printed shapes on paper. I prefer physical 3d items in designated boxes, in this case, 5 boxes with one shape per box. You would potentially need 16 x 4 shapes because it's possible to have a span value of 1,1,5,10,22 for 649, therefore you would need two of the same objects.
You also need a CUE for a photo that needs a description in a future state. Such as, describe the location of the photo you'll see Friday 10:00pm. This is where it may get tricky.
Does anyone have some advice on how to CUE a future photo, but not describing the photo itself, rather, it's location as shown in the photo. This is important.
If anyone is willing to try this method please keep in touch. You can find me via
www.psiNation.orgThanks
James
http://www.psination.org/rv/lotto/jdclotto.pdf
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